mysql--多表联合查询-白红宇

mysql--多表联合查询

阅读量：5087 次

发布时间：2019-06-13

本文共 8533 字，大约阅读时间需要 28 分钟。

先准备两张表

company.employee

company.department

#建表create table department(id int,name varchar(20) );create table employee(id int primary key auto_increment,name varchar(20),sex enum('male','female') not null default 'male', age int, dep_id int ); #插入数据 insert into department values (200,'技术'), (201,'人力资源'), (202,'销售'), (203,'运营'); insert into employee(name,sex,age,dep_id) values ('egon','male',18,200), ('alex','female',48,201), ('wupeiqi','male',38,201), ('yuanhao','female',28,202), ('liwenzhou','male',18,200), ('jingliyang','female',18,204) ; #查看表结构和数据 mysql> desc department; +-------+-------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-------+-------------+------+-----+---------+-------+ | id | int(11) | YES | | NULL | | | name | varchar(20) | YES | | NULL | | +-------+-------------+------+-----+---------+-------+ mysql> desc employee; +--------+-----------------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +--------+-----------------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | name | varchar(20) | YES | | NULL | | | sex | enum('male','female') | NO | | male | | | age | int(11) | YES | | NULL | | | dep_id | int(11) | YES | | NULL | | +--------+-----------------------+------+-----+---------+----------------+ mysql> select * from department; +------+--------------+ | id | name | +------+--------------+ | 200 | 技术 | | 201 | 人力资源 | | 202 | 销售 | | 203 | 运营 | +------+--------------+ mysql> select * from employee; +----+------------+--------+------+--------+ | id | name | sex | age | dep_id | +----+------------+--------+------+--------+ | 1 | egon | male | 18 | 200 | | 2 | alex | female | 48 | 201 | | 3 | wupeiqi | male | 38 | 201 | | 4 | yuanhao | female | 28 | 202 | | 5 | liwenzhou | male | 18 | 200 | | 6 | jingliyang | female | 18 | 204 | +----+------------+--------+------+--------+ 二 多表连接查询

#重点：外链接语法SELECT 字段列表    FROM 表1 INNER|LEFT|RIGHT JOIN 表2    ON 表1.字段 = 表2.字段;

1 交叉连接：不适用任何匹配条件。生成笛卡尔积

mysql> select * from employee,department;+----+------------+--------+------+--------+------+--------------+| id | name       | sex    | age  | dep_id | id   | name         |+----+------------+--------+------+--------+------+--------------+|  1 | egon       | male   |   18 |    200 |  200 | 技术         ||  1 | egon       | male   |   18 |    200 |  201 | 人力资源     ||  1 | egon       | male   |   18 |    200 |  202 | 销售         ||  1 | egon       | male   |   18 |    200 |  203 | 运营         ||  2 | alex       | female |   48 |    201 |  200 | 技术         ||  2 | alex       | female |   48 |    201 |  201 | 人力资源     ||  2 | alex       | female |   48 |    201 |  202 | 销售         ||  2 | alex       | female |   48 |    201 |  203 | 运营         ||  3 | wupeiqi    | male   |   38 |    201 |  200 | 技术         ||  3 | wupeiqi    | male   |   38 |    201 |  201 | 人力资源     ||  3 | wupeiqi    | male   |   38 |    201 |  202 | 销售         ||  3 | wupeiqi    | male   |   38 |    201 |  203 | 运营         ||  4 | yuanhao    | female |   28 |    202 |  200 | 技术         ||  4 | yuanhao    | female |   28 |    202 |  201 | 人力资源     ||  4 | yuanhao    | female |   28 |    202 |  202 | 销售         ||  4 | yuanhao    | female |   28 |    202 |  203 | 运营         ||  5 | liwenzhou  | male   |   18 |    200 |  200 | 技术         ||  5 | liwenzhou  | male   |   18 |    200 |  201 | 人力资源     ||  5 | liwenzhou  | male   |   18 |    200 |  202 | 销售         ||  5 | liwenzhou  | male   |   18 |    200 |  203 | 运营         ||  6 | jingliyang | female |   18 |    204 |  200 | 技术         ||  6 | jingliyang | female |   18 |    204 |  201 | 人力资源     ||  6 | jingliyang | female |   18 |    204 |  202 | 销售         ||  6 | jingliyang | female |   18 |    204 |  203 | 运营         |+----+------------+--------+------+--------+------+--------------

2 内连接：只连接匹配的行

#找两张表共有的部分，相当于利用条件从笛卡尔积结果中筛选出了正确的结果#department没有204这个部门，因而employee表中关于204这条员工信息没有匹配出来mysql> select employee.id,employee.name,employee.age,employee.sex,department.name from employee inner join department on employee.dep_id=department.id; +----+-----------+------+--------+--------------+ | id | name | age | sex | name | +----+-----------+------+--------+--------------+ | 1 | egon | 18 | male | 技术 | | 2 | alex | 48 | female | 人力资源 | | 3 | wupeiqi | 38 | male | 人力资源 | | 4 | yuanhao | 28 | female | 销售 | | 5 | liwenzhou | 18 | male | 技术 | +----+-----------+------+--------+--------------+ #上述sql等同于 mysql> select employee.id,employee.name,employee.age,employee.sex,department.name from employee,department where employee.dep_id=department.id;

3 外链接之左连接：优先显示左表全部记录

#以左表为准，即找出所有员工信息，当然包括没有部门的员工#本质就是：在内连接的基础上增加左边有右边没有的结果mysql> select employee.id,employee.name,department.name as depart_name from employee left join department on employee.dep_id=department.id; +----+------------+--------------+ | id | name | depart_name | +----+------------+--------------+ | 1 | egon | 技术 | | 5 | liwenzhou | 技术 | | 2 | alex | 人力资源 | | 3 | wupeiqi | 人力资源 | | 4 | yuanhao | 销售 | | 6 | jingliyang | NULL | +----+------------+--------------+

4 外链接之右连接：优先显示右表全部记录

#以右表为准，即找出所有部门信息，包括没有员工的部门#本质就是：在内连接的基础上增加右边有左边没有的结果mysql> select employee.id,employee.name,department.name as depart_name from employee right join department on employee.dep_id=department.id; +------+-----------+--------------+ | id | name | depart_name | +------+-----------+--------------+ | 1 | egon | 技术 | | 2 | alex | 人力资源 | | 3 | wupeiqi | 人力资源 | | 4 | yuanhao | 销售 | | 5 | liwenzhou | 技术 | | NULL | NULL | 运营 | +------+-----------+--------------+

5 全外连接：显示左右两个表全部记录

全外连接：在内连接的基础上增加左边有右边没有的和右边有左边没有的结果#注意：mysql不支持全外连接 full JOIN#强调：mysql可以使用此种方式间接实现全外连接select * from employee left join department on employee.dep_id = department.id union select * from employee right join department on employee.dep_id = department.id ; #查看结果 +------+------------+--------+------+--------+------+--------------+ | id | name | sex | age | dep_id | id | name | +------+------------+--------+------+--------+------+--------------+ | 1 | egon | male | 18 | 200 | 200 | 技术 | | 5 | liwenzhou | male | 18 | 200 | 200 | 技术 | | 2 | alex | female | 48 | 201 | 201 | 人力资源 | | 3 | wupeiqi | male | 38 | 201 | 201 | 人力资源 | | 4 | yuanhao | female | 28 | 202 | 202 | 销售 | | 6 | jingliyang | female | 18 | 204 | NULL | NULL | | NULL | NULL | NULL | NULL | NULL | 203 | 运营 | +------+------------+--------+------+--------+------+--------------+ #注意 union与union all的区别：union会去掉相同的纪录

三符合条件连接查询

#示例1：以内连接的方式查询employee和department表，并且employee表中的age字段值必须大于25,即找出公司所有部门中年龄大于25岁的员工select employee.name,employee.age from employee,department    where employee.dep_id = department.id    and age > 25; #示例2：以内连接的方式查询employee和department表，并且以age字段的升序方式显示 select employee.id,employee.name,employee.age,department.name from employee,department where employee.dep_id = department.id and age > 25 order by age asc;

四子查询

#1：子查询是将一个查询语句嵌套在另一个查询语句中。#2：内层查询语句的查询结果，可以为外层查询语句提供查询条件。#3：子查询中可以包含：IN、NOT IN、ANY、ALL、EXISTS 和 NOT EXISTS等关键字 #4：还可以包含比较运算符：= 、 !=、> 、

1 带IN关键字的子查询

#查询employee表，但dep_id必须在department表中出现过select * from employee    where dep_id in (select id from department);

2 带比较运算符的子查询

#查询employee表，但dep_id必须在department表中出现过 select * from employee where dep_id in ( select id from department); 2 带比较运算符的子查询

#比较运算符：=、!=、>、>=、<、<=、<>#查询平均年龄在25岁以上的部门名select id,name from department where id in (select dep_id from employee group by dep_id having avg(age) > 25); #查看技术部员工姓名 select name from employee where dep_id in (select id from department where name='技术'); #查看不足1人的部门名 select name from department where id in (select dep_id from employee group by dep_id having count(id) <=1);

3 带EXISTS关键字的子查询

EXISTS关字键字表示存在。在使用EXISTS关键字时，内层查询语句不返回查询的记录。

而是返回一个真假值。True或False

当返回True时，外层查询语句将进行查询；当返回值为False时，外层查询语句不进行查询

#department表中存在dept_id=203，Turemysql> select * from employee    ->     where exists    ->         (select id from department where id=200); +----+------------+--------+------+--------+ | id | name | sex | age | dep_id | +----+------------+--------+------+--------+ | 1 | egon | male | 18 | 200 | | 2 | alex | female | 48 | 201 | | 3 | wupeiqi | male | 38 | 201 | | 4 | yuanhao | female | 28 | 202 | | 5 | liwenzhou | male | 18 | 200 | | 6 | jingliyang | female | 18 | 204 | +----+------------+--------+------+--------+ #department表中存在dept_id=205，False mysql> select * from employee -> where exists -> (select id from department where id=204); Empty set (0.00 sec)

转载于:https://www.cnblogs.com/DE_LIU/p/7505521.html

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